Nuprl Lemma : fpf-sub_weakening 0,22

A:Type, B:(AType), eq:EqDecider(A), fg:a:A fp B(a). f = g  f  g 
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DefinitionsA & B, f(x), b, x  dom(f), Top, P  Q, Prop, a:A fp B(a), EqDecider(T), f  g, xt(x), x:AB(x), x(s), t  T
Lemmasfpf-sub wf, deq wf, fpf wf, fpf-trivial-subtype-top, fpf-dom wf, assert wf, fpf-ap wf

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